two sum leetcode

Topic tags :- Array, Hash Table 

Question type :- Easy

Question link : Two Sum

Note : Try yourself before seeing solution here.

Question :

Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

You can return the answer in any order.

 
Example 1:

Input: nums = [2,7,11,15], target = 9
Output: [0,1]
Output: Because nums[0] + nums[1] == 9, we return [0, 1].

Example 2:

Input: nums = [3,2,4], target = 6
Output: [1,2]

Example 3:

Input: nums = [3,3], target = 6
Output: [0,1]
 

Constraints:

2 <= nums.length <= 104
-109 <= nums[i] <= 109
-109 <= target <= 109

Only one valid answer exists.
 

Follow-up: Can you come up with an algorithm that is less than O(n2) time complexity?

Solutions : in Java

Solution 1:

class Solution {
   public int[] twoSum(int[] nums, int target) {
        
        for (int i = 1; i < nums.length; i++) 
            for (int j = i; j < nums.length; j++) 
                if (nums[j] + nums[j - i] == target) 
                    return new int[]{j - i, j};
        
        return null;

    }
}

Runtime: 1 ms
Memory Usage: 41.9 MB
Solution link : click here

Solution 2:

class Solution {
    public int[] twoSum(int[] nums, int target) {
        for(int i=0;i<nums.length;i++){
            for(int j=1;j<nums.length;j++){
                if(i==j){
                    continue;
                }
                if(nums[i]+nums[j]== target){
                    return new int[] {Math.min(i,j),Math.max(i,j)};
                }
            }
        }
        return nums;
    }
}

Runtime: 155 ms
Memory Usage: 42 MB
Solution link : click here

Solution 3:

class Solution {
    public int[] twoSum(int[] nums, int target) {
        int arr[] = new int[2];
        for(int i=0;i<nums.length;i++){
            for(int j=1;j<nums.length;j++){
                if(i==j){
                    continue;
                }
                if(nums[i]+nums[j]== target){
                    arr[0] = Math.min(i,j);;
                    arr[1] = Math.max(i,j);
                    return arr;
                }
            }
        }
        return arr;
    }
}

Runtime: 180 ms
Memory Usage: 41.9 MB
Solution link : click here

Solution 4:

class Solution {
    public int[] twoSum(int[] nums, int target) {
        for(int a=0;a<nums.length;a++){
            for(int b=a+1;b<nums.length;b++){
                if(nums[a]+nums[b]==target)
                {
                    return new int[] {a ,b};
                }
            }
        }
        throw new IllegalArgumentException("No two sum solution");
    }
}

Runtime: 44 ms
Memory Usage: 40 MB
Solution link : click here

Thank you

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